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# Lasso - A free implementation of the Liberty Alliance specifications.
#
# Copyright (C) 2004-2007 Entr'ouvert
# http://lasso.entrouvert.org
#
# Authors: See AUTHORS file in top-level directory.
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
import re
import string
def format_as_camelcase(var):
'''Format an identifier name into CamelCase'''
if '_' in var:
return format_underscore_as_camelcase(var)
if var[0] in string.uppercase:
var = var[0].lower() + var[1:]
var = re.sub(r'([a-z])(ID)([A-Z]|$)', r'\1Id\3', var) # replace standing ID by Id
return var
def format_as_underscored(var):
'''Format an identifier name into underscored_name'''
def rep(s):
return s.group(0)[0] + '_' + s.group(1).lower()
var = re.sub(r'[a-z0-9]([A-Z])', rep, var).lower()
var = var.replace('id_wsf2_', 'idwsf2_')
var = var.replace('_saslresponse', '_sasl_response')
return var
def format_underscore_as_camelcase(var):
'''Format an underscored identifier name into CamelCase'''
def rep(s):
return s.group(1)[0].upper() + s.group(1)[1:]
var = re.sub(r'_([A-Za-z0-9]+)', rep, var)
var = re.sub(r'([a-z])(ID)([A-Z]|$)', r'\1Id\3', var) # replace standing ID by Id
return var
def last(x):
return x[len(x)-1]
def common_prefix(x,y):
max = min(len(x),len(y))
last = 0
for i in range(max):
if x[i] != y[i]:
return min(i,last+1)
if x[i] == '_':
last = i
return max
def pgroup(group,prev):
level, l = group
i = 0
for x in l:
if i == 0:
prefix = prev
else:
prefix = level
if isinstance(x,tuple):
pgroup(x,prefix)
else:
print prefix * ' ' + x[prefix:]
i = i + 1
def group(list):
list.sort()
pile = [(0,[])]
prev = ""
for x in list:
l, g = last(pile)
u = common_prefix(x,prev)
# Find the good level of insertion
while u < l:
pile.pop()
l, g = last(pile)
# Insert here
if u == l:
g.append(x)
elif u > l:
t = (u, [g.pop(),x])
g.append(t)
pile.append(t)
prev = x
return pile[0]
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