Solving the chicken-and-egg problem of creating the

"fdp-info-${LANG}.xml" file by using a simple shell script to pick
out the document type.  This is needed because, without the
"fdp-info-${LANG}.xml" file, a new document will not validate and the
xsltproc script "doctype.xsl" cannot determine the document type.  To
avoid nasty in-place sed(1)'ing to circumvent the problem, I'll opt
for a non-XML solution.

2 files changed, 26 insertions, 0 deletions

diff --git a/packaging/doctype b/packaging/doctype
new file mode 100755
index 0000000..a10441f
--- /dev/null
+++ b/packaging/doctype
@@ -0,0 +1,14 @@
+#!/bin/sh
+########################################################################
+# Script to print the document type, without needing the XML document
+# to validate.  Get the document type from the first argument to the
+# <!DOCTYPE> element, which should be either "book" or "article".
+#
+# Use it like this:
+# doctype file.xml
+#
+# If you know the XML file WILL VALIDATE, you may use the "doctype.xsl"
+# script instead.  If not, use this one
+########################################################################
+egrep '^[[:space:]]*<!DOCTYPE' $*					|
+awk '{print $2 "info"}'
diff --git a/packaging/doctype.xsl b/packaging/doctype.xsl
index 8cf535e..eb6e41a 100644
--- a/packaging/doctype.xsl
+++ b/packaging/doctype.xsl
@@ -1,5 +1,17 @@
 <?xml version="1.0" encoding="UTF-8"?>
 
+<!--
+	This stylesheet will output the word "articleinfo" or
+	"bookinfo" by finding either the <article> or <book> XML 
+	element in the document.  Use it like this:
+
+	xsltproc doctype.xsl file.xml
+
+	The "file.xml" file MUST VALIDATE in order for the results
+	to be meaningful.  If the document might not validate, use the
+	"doctype" shell script instead.
+  -->
+
 <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output omit-xml-declaration="yes"/>
   <xsl:template match="/article">articleinfo</xsl:template>