1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
|
#!/usr/bin/python
# -*- mode:python -*-
# Checks how many bugs in Bugzilla have the same hash.
#
# Please do not run this script unless it's neccessary to do so.
# It forces Bugzilla to send data related to thousands of bug reports.
from bugzilla import RHBugzilla
from optparse import OptionParser
import sys
import os.path
import subprocess
import re
parser = OptionParser(version="%prog 1.0")
parser.add_option("-u", "--user", dest="user",
help="Bugzilla user name (REQUIRED)", metavar="USERNAME")
parser.add_option("-p", "--password", dest="password",
help="Bugzilla password (REQUIRED)", metavar="PASSWORD")
parser.add_option("-b", "--bugzilla", dest="bugzilla",
help="Bugzilla URL (defaults to Red Hat Bugzilla)", metavar="URL")
(options, args) = parser.parse_args()
if not options.user or len(options.user) == 0:
parser.error("User name is required.\nTry {0} --help".format(sys.argv[0]))
if not options.password or len(options.password) == 0:
parser.error("Password is required.\nTry {0} --help".format(sys.argv[0]))
if not options.bugzilla or len(options.bugzilla) == 0:
options.bugzilla = "https://bugzilla.redhat.com/xmlrpc.cgi"
bz = RHBugzilla()
bz.connect(options.bugzilla)
bz.login(options.user, options.password)
buginfos = bz.query({'status_whiteboard_type':'allwordssubstr','status_whiteboard':'abrt_hash'})
print "{0} bugs found.".format(len(buginfos))
hashes = {}
for buginfo in buginfos:
match = re.search("abrt_hash:([^ ]+)", buginfo.status_whiteboard)
if not match:
continue
hash = match.group(1)
if not hash:
continue
if hash in hashes:
hashes[hash].append(buginfo.bug_id)
else:
hashes[hash] = [ buginfo.bug_id ]
print hash
bz.logout()
for hash, ids in hashes.items():
if len(ids) > 1:
print "Duplicates found: ", reduce(lambda x,y: str(x)+", "+str(y), ids)
|