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# python-bugzilla - a Python interface to bugzilla using xmlrpclib.
#
# Copyright (C) 2007,2008 Red Hat Inc.
# Author: Will Woods <wwoods@redhat.com>
#
# This program is free software; you can redistribute it and/or modify it
# under the terms of the GNU General Public License as published by the
# Free Software Foundation; either version 2 of the License, or (at your
# option) any later version. See http://www.gnu.org/copyleft/gpl.html for
# the full text of the license.
from bugzilla3 import Bugzilla3
from rhbugzilla import RHBugzilla
import xmlrpclib
def getBugzillaClassForURL(url):
s = xmlrpclib.ServerProxy(url)
# RH Bugzilla method
prodinfo = {}
try:
prodinfo = s.bugzilla.getProdInfo()
return RHBugzilla
except xmlrpclib.Fault:
pass
try:
r = s.Bugzilla.version()
version = r['version']
if version.startswith('3.'):
return Bugzilla3
except xmlrpclib.Fault:
pass
return None
class Bugzilla(object):
'''Magical Bugzilla class that figures out which Bugzilla implementation
to use and uses that.'''
def __init__(self,**kwargs):
if 'url' in kwargs:
c = getBugzillaClassForURL(kwargs['url'])
if c:
self.__class__ = c
c.__init__(self,**kwargs)
# FIXME no url? raise an error or something here, jeez
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